Two Absolute Values in One Problem
Let’s get started!
Solving for x
First tackle |2x – 3| = 9. Solve for x, using the Steps for Success for Absolute Values!
Step 1: Write the equation twice without the absolute value bars.
2x – 3 = 9 and 2x – 3 = 9
Step 2: With one of the equations, for everything that was inside the absolute value bars, change the sign to the opposite.
2x – 3 = 9 and –2x + 3 = 9
Step 3: Solve each equation for the unknown.
We’ll start with 2x – 3 = 9
We have 2x = 12. Now let’s divide both sides by 2 to get x alone.
Now don’t forget the second equation of –2x + 3 = 9! We need to solve for the unknown with that one as well.
We have –2x = 6. Now let’s divide both sides by –2 to get x alone.
We have determined that x = 6 and x = –3
Step 4: Check your work! Substitute the answers you got back into the original equation.
Let’s check x = 6. We’ll substitute 6 in for x:
|2x – 3| = 9
|2(6) – 3| = 9
|12 – 3| = 9
|9| = 9
Correct!
Let’s check x = –3. We’ll substitute –3 in for x:
|2x – 3| = 9
|2(–3) – 3| = 9
|–6 – 3| = 9
|–9| = 9
Correct!
Solving for y
Now we need to go through this process to solve for y.
|3 – y| = 7
Step 1: Write the equation twice without the absolute value bars.
3 – y = 7 and 3 – y = 7
Step 2: With one of the equations, for everything that was inside the absolute value bars, change the sign to the opposite.
3 – y = 7 and –3 + y = 7
Step 3: Solve each equation for the unknown.
We’ll start with 3 – y = 7
We have – y = 4. Now let’s divide both sides by –1 to get y alone.
Now don’t forget the second equation of –3 + y = 7! We need to solve for the unknown with that one as well.
y = 10
We have determined that y = –4 and y = 10
Step 4: Check your work! Substitute the answers you got back into the original equation.
Let’s check y = –4. We’ll substitute –4 in for y:
|3 – y| = 7
|3 – (–4)| = 7
|3 + 4| = 7
|7| = 7
Correct!
Let’s check y = 10. We’ll substitute 10 in for y:
|3 – y| = 7
|3 – 10| = 7
|–7| = 7
Correct!
We know that:
x = 6 or –3
y = –4 or 10
Let’s map out the different scenarios. First I hold the value for x the same and go through the different values of y (Scenarios 1 and 2). Then I go to the next value for x, and again go through the different values of y (Scenarios 3 and 4).
Let’s remind ourselves of what the question was:
We would chose Option a and Option c.
We wouldn’t choose Option b since the sign is wrong. We wouldn’t choose Option d since that didn’t match any of our solutions.
Great work!!